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The kinetic energy of a particle, execut...

The kinetic energy of a particle, executing S.H.M., is 16 J when it is in its mean position. If the amplitude of oscillation is 25 cm, and the mass of the particle is 5.12 kg, the time period of its oscillations is :

A

`pi//5` s

B

`2pi` s

C

`20pi` s

D

`5pi` s.

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/(2)m omega^(2)A^(2)=16`
`(1)/(2)m omega^(2)=(16)/(A^(2))=(160000)/(25xx25)`
`(1)/(2)xx5.12omega^(2)=256`
`omega^(2)=(512)/(5.12)=100`
`omega=10" or "(2pi)/(T)=10`
`T=(pi)/(5)` s.
Correct choice is (a).
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