A simple pendulum is executing simple harmonic motion with a time period T. If the length of pendulum is increased by 21 %, the % increase in the time period of the pendulum of increased length is :

Options

A. 0.1
B. 0.21
C. 0.3
D. 0.5

Answer

A

Explanation

Here `" "(T_(2))/(T_(1))=sqrt((121)/(100))=(11)/(10)`
`:." "T_(2)=(11)/(10)T_(1)`
% increase in time period `=(T_(2)-T_(1))/(T_(1))xx100`
`=((11)/(10)T_(1)-T_(1))/(T_(1))xx100=10%`.
Correct choice is (a).