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Two springs A and B having spring consta...

Two springs A and B having spring constant `k_(A)` and `k_(B)(k_(A)=2k_(B))` are stretched by applying force of equal magnitude. If energy stored in spring A is `E_(A)` then energy stored in B will be :

A

`2E_(A)`

B

`E_(A)//4`

C

`E_(A)//2`

D

`4E_(A)`.

Text Solution

Verified by Experts

The correct Answer is:
A
`(E_(A))/(E_(B))=((F^(2))/(2k_(A)))/((F^(2))/(2k_(B)))=(k_(B))/(k_(A))=(1)/(2)impliesE_(B)=2E_(A)`
Correct choice is (a).
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