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If a simple harmonic motion is represent...

If a simple harmonic motion is represented by `(d^(2)X)/(dt^(2))+alphax=0` its time period is :

A

`2pi//alpha`

B

`2pi//sqrt(alpha)`

C

`2pi alpha`

D

`2pi sqrt(alpha)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(d^(2)X)/(dt^(2))+alphax=0`
Comparing it with standard equation of SHM.
`(d^(2)X)/(dt^(2))+w^(2)X=0` we have `w^(2)=a`
Time period `T=(2pi)/(w)=(2pi)/(sqrt(a))`
So the correct choice is (b).
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