A mass hangs at the end of a massless spring and oscillates up and down at its natural frequency f. If the spring is cut at the midpoint and and mass reattached at the end, the frequency of oscillation is :

Options

A. `sqrt(2)f`
B. `2sqrt(2)`
C. `f//2`
D. `f sqrt(2)`.

Answer

A

Explanation

Frequency of oscillation of spring is given by
`v=(1)/(2pi) sqrt((K)/(m))`
Since spring is cut into equal parts `:.` spring constant becomes two times and hence frequency becomes `sqrt(2)` times
So correct choice is a.