Two particles are executing simple harmonic motion. At an instant of time t their displacement are
`y_(1)=a cos(omegat)`
and `" "y_(2)=a sin(omegat)`
Then the phase difference between `y_(1)` and `y_(2)` is:

Options

A. `120^(@)`
B. `90^(@)`
C. `180^(@)`
D. zero.

Answer

B

Explanation

`y_(1)=a cos omega t=a sin(omega t+pi//2)`
`y_(2)=a sin omegat`.
`:.` Phase difference between `y_(1)` and `y_(2)` is `90^(@)` Correct choice is (a).