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A lift is ascending by acceleration g//3...

A lift is ascending by acceleration `g//3`. What will be the time period of a simple pendulum suspended from its ceiling if its time period in stationary lift is T?

A

`T//2`

B

`(sqrt(3//4))T`

C

`T//4`

D

`(sqrt(3//2))T`.

Text Solution

Verified by Experts

The correct Answer is:
B
`T=2pi sqrt((l)/(g))` and `T.=2pi sqrt((l)/(g+a))`
`implies" "T.=2pi sqrt((l)/(g+(g)/(3)))`
`:." "T.=2pi sqrt((3l)/(4g))`
`implies" "T.=sqrt((3)/(4)).T.`
Correct choice is (b)`.
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