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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum is T in a stationary lift. If the lift moves upward with acceleration of 8g the time period will :

A

becomes T/2

B

becomes T/3

C

remains same

D

none of these.

Text Solution

Verified by Experts

The correct Answer is:
B
In stationary lift `T=2pi sqrt((l)/(g))`
When lift ascends then apparent acceleration is `g.=g+a=g+8g=9g`
`:." "T.=2pi sqrt((l)/(g.))=2pi sqrt((l)/(9g))impliesT.=(T)/(3)`
Correct choice is (b).
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