The particle executing simple harmonic motion has kinetic energy `K_(0)cos^(2)omegat`. The maximum values of the potential energy and the total energy are respectively :

Options

A. `(K_(0))/(2)` and `K_(0)`
B. `K_(0)` and `2K_(0)`
C. `K_(0)` and `K_(0)`
D. 0 and `2K_(0)`.

Answer

C

Explanation

Kinetic energy `=K_(0)cos^(2)omega t`
When ` cos^(2)omega t=1`
then kinetic energy `=K_(0)` (maximum).
Thus maximum value of potential energy `=K_(0)`
Maximum value of total energy
= maximum value of potential energy `=K_(0)`
Correct choice is ( c ).