A sphere of brass is suspended to a vertical spring and oscillates with frequency f'. The ball is now immersed is non-viscous liquid whose density is `(1)/(10)` th of density of brass. If the sphere remains vibrating in the liquid the frequency f now will be :

Options

A. `f' = f`
B. `f'=sqrt((10)/(9))f`
C. `f'=sqrt((10)/(9))f`
D. `f'=sqrt((9)/(10))f`.

Answer

A

Explanation

`T=2pi sqrt((m)/(k))impliesf=(1)/(T)=(1)/(2pi)sqrt((k)/(m))`
When ball is immersed in the liqiud then m and k remain the same so frequencyy also remains the same. Thus correct choice is (a).