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A mass M is suspended from a light sprin...

A mass M is suspended from a light spring. An additional mass m added displaces the spring further by a distance x. Now the combined mass will oscillate on the spring with a period :

A

`T=2pi sqrt((mg)/(x(M+m)))`

B

`T=2pi sqrt(((M+m)x)/(mg))`

C

`T=2pi sqrt(((M+m))/(mgx))`

D

`T=2pi sqrt((mgx)/((M+m)))`

Text Solution

Verified by Experts

The correct Answer is:
B

`T=2pi sqrt(("mass")/("spring const."))`
Now `k=("Force")/("extension")("mg")/("x")`.
When total mass is `M+m`.
Then `T=2pi sqrt((M+m)/((mg)/(x)))=2pi sqrt(((M+m)x)/(mg))`.
So the correct choice is (b).
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