Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm.
The period of oscillation in seconds is :

Options

A. `pi`
B. `2pi`
C. `3pi`
D. `4pi`

Answer

B

Explanation

`T=2pi sqrt((x_(2)^(2)-x_(1)^(2))/(u_(1)^(2)-u_(2)^(2)))=2pi sqrt((16-9)/(16-9))=2pi`
So correct choice is (b).