Paragraph : A particle vibrates in S.H.M. along a straight line. Its velocity is 4 cm/s when its displacement is 3 cm and velocity is 3 cm/s when displacement is 4 cm.
The maximum value of acceleration is :

Options

A. `2" cm"//"s"^(2)`
B. `3" cm"//"s"^(2)`
C. `4" cm"//"s"^(2)`
D. `5" cm"//"s"^(2)`.

Answer

D

Explanation

`U_("max")=omega^(2)r=((2pi)/(T))^(2)xx r=((2pi)/(2pi))^(2)xx5`
`=5" cm"//"s"^(2)`
So correct choice is (d).