Two springs A and B having spring constant `k_(A)` and `k_(B)(k_(A)=2k_(B))` are stretched by applying force of equal magnitude. If energy stored in spring A is `E_(A)` then energy stored in B will be :

Options

A. `2E_(A)`
B. `E_(A)//2`
C. `E_(A)//4`
D. `4E_(A)`.

Answer

A

Explanation

Energy of the spring `U=(1)/(2)kx^(2)=(F^(2))/(2k)`
`:." "(E_(A))/(E_(B))=((F^(2))/(2k_(A)))/((F^(2))/(2k_(B)))=(k_(B))/(k_(A))=(k_(B))/(2k_(B))=(1)/(2)impliesE_(B)=2E_(A)`.
Correct choice is ( c )