The angular velocities of three bodies in simple harmonic motion are `omega_(1),.omega_(2),omega_(3)` with their respective amplitudes as `A_(1),A_(2),A_(3)`. If all the three bodies have the same mass and velocity, then :

Options

A. `A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`
B. `A_(1)omega_(1)^(2)=A_(2)omega_(2)^(2)=A_(3)omega_(3)^(2)`
C. `A_(1)^(2)omega_(1)=A_(2)^(2)omega_(2)=A_(3)^(2)omega_(3)`
D. `A_(1)^(2)omega_(1)^(2)=A_(2)^(2)omega_(2)^(2)=A_(3)^(2)omega_(3)^(2)`.

Answer

A

Explanation

Max velocity `v=r omega`
Since velocity is same
`:." "A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`
Correct choice is (a).