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A mass M is suspended from a light sprin...

A mass M is suspended from a light spring. An additional mass m added displaces the spring further by a distance x. Now the combined mass will oscillate on the spring with a period :

A

`T=2pi sqrt((mg)/(x(M+m)))`

B

`T=2pi sqrt(((M+m)x)/(mg))`

C

`T=(pi)/(2)sqrt((mg)/(X(M+m)))`

D

`T=2pi sqrt(((M+m))/(mg))`.

Text Solution

Verified by Experts

The correct Answer is:
B
Here `mg=kximpliesk=mg//x`.
`T=2pi sqrt(((M+m))/(K))impliesT=2pi sqrt(((M+m)x)/(mg))`.
So correct choice is (b).
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