A compound slab is composed of two parallel layers of different materials with thickness 3 cm and 2 cm. The temp of outer face of the slab are maintained at `100^(@)C` and `0^(@)C` If the conductivities are `0.36` and `0.16` cgs units, then the temp. of junction is :

Options

A. `40^(@)C`
B. `60^(@)C`
C. `100^(@)C`
D. `50^(@)C`

Answer

B

Explanation

In steady state
`H_(1)=H_(2)`.
`(k_(1)A(T_(1)-T))/(d_(1))=(k_(2)A(T-T_(2)))/(d_(2))`
`(0.3xx(100-T))/(3)=(0.16xx(T-0))/(2)`
`rArr" "T=60^(@)c`
Thus correct choice is (b).