The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures `T _(1)` and `T_(2)` rod in a steady state is given by :

Options

A. `(dQ)/(dt)=(k(T_(1)-T_(2)))/(LA)`
B. `(dQ)/(dt)=kLA(T_(1)-T_(2))`
C. `(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
D. `(dQ)/(dt)=(kL(T_(1)-T_(2)))/(A)`

Answer

C

Explanation

As `(dQ)/(dt)=(kA(T_(1)-T_(2)))/(L)`
Correct choice is (c ).