An electron moving with a speed of 10^(7...

An electron moving with a speed of `10^(7)ms^(-1)` traces a circular path of radius 0-57 cm, when subjected to a magnetic field of `10^(-2)` T perpendicular to the direction of motion of electron, what is elm ?

`1.76xx10^(9)C//kg^(-1)`

`1.76xx10^(10)C//kg^(-1)`

`1.76xx10^(-12)C//kg^(-1)`

`1.76xx10^(11)C//kg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`e//m=(v)/(Br)=(10^(7)xx1)/(10^(-2)xx0*57xx10^(-2))=(100)/(57)xx10^(11)`
`=1*76xx10^(11)C kg^(-1)`

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