A stream of electrons moving with `3xx10^(7)ms^(-1)` gets deflected by electric field of 18 V/ cm normal to their path. What is its transverse deflection in travelling through a horizontal distance of 10 cm in the field ? `(m_(e)=9xx10^(-31)kg)`:

Options

A. 0.177 cm
B. 1.77 cm
C. 17.7 cm
D. 1. 77 cm

Answer

A

Explanation

Here, acceleration
`a=(X*e)/(m)=(1800xx1*6xx10^(-19))/(9xx10^(-31))=32xx10^(13)`
`x=(10)/(100)=3xx10^(7)x t or t=(1)/(3xx10^(8))` sec.
`y=(1)/(2) at^(2)=(1*6)/(9)=0*177 cm`