Two beams P and Q of light of the same wavelength fall upon the same metal surface causing photoemission of electrons. The photoelectric current produced by P is four times that produced by Q. Which of the following gives the ratio
`("wave amplitude of beam P")/("wave amplitude of beam Q")`?

Options

A. `(1)/(4)`
B. `(1)/(2)`
C. 2
D. 4

Answer

C

Explanation

`("Wave amplitude of beamP")/("Wave amplitude of beam Q")=(("Current of P")^(1//2))/(("Current of Q")^(1//2))=((4)/(1))^((1//2))=2`