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A 20 a.m.u. atom emits photon of 6.6Å wh...

A 20 a.m.u. atom emits photon of `6.6Å` while making a transition from excited state to ground state. The recoil energy of the atom will be :

A

`1.5xx10^(-23)J`

B

`3.5xx10^(-23)J`

C

`5.1xx10^(-23)J`

D

`7.5xx10^(-23)J`

Text Solution

Verified by Experts

The correct Answer is:
C
`:.p=(h)/(lambda)`
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