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The potential difference applied to an X...

The potential difference applied to an X-ray tube is 5kV and current is 3.2 mA. Then no. of electrons striking the target per sec is :

A

`2xx10^(16)`

B

`5xx10^(6)`

C

`1xx10^(17)`

D

`4xx10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`n=(q)/(e)=("it")/(e)`
`i=3*2xx10^(-3)A t=1s`
`:.n=(3*2xx10^(-3))/(xx1*6xx10^(-19))=2xx10^(16)`
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