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A charged oil drop is suspended in a uni...

A charged oil drop is suspended in a uniform field of `3xx10^(4)` V/m so that it neither falls nor rises. The charge on drop will be (Take mass of charge `=9.9 X10^(-15)kg` and `g=10m//s^(2)`).

A

`2.3xx10^(-18)C`

B

`3.3xx10^(-18)C`

C

`4.8xx10^(-18)C`

D

`1.6xx10^(-18)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`qE=mg`
`:.q=(mg)/(E)=(9.9xx10^(-15)xx10)/(3xx10^(4))`
`:.q=3.3xx10^(-18)C`
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