After absorbing a slowly moving neutron of Mass `m_(N)` (momentum `~~0` ) a nucleus of mass M breaks into two nuclei of masses `m_(1)and5m_(1) (6m_(1)=M+m_(N))` respectively. If the de Broglie wavelength of the nucleus with mass `m_(1)` is `lamda` the de Broglie wavelength of the nucleus will be

Options

A. `5lamda`
B. `lamda//5`
C. `lamda`
D. `25lamda`

Answer

C

Explanation

`P=0`
`P_(1)=P+P_(2)`
`P_(1)=P_(2)`
`0+P_(1)+P_(2)`
`(P_(1)=-P_(2))`
`lambda_(1)=(h)/(P_(1))`
`lambda_(2)=(h)/(P_(2))`
`|lambda_(1)|=|lambda_(2)|`
`lambda_(1)=lambda_(2)`