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The ratio of number of electrons present...

The ratio of number of electrons present I four shells of an element is `1 : 4 : 4 : 1`, fourth shell is the valence shell . Then mass of total positive charge present in the atom is ____________ times to that of mass of electron

A

36 , 704

B

27 , 555

C

18 , 370

D

55, 110

Text Solution

Verified by Experts

The correct Answer is:
1

The electronic configuration of the element is
`{:(K,L,M,N),(2,8,8,2):}`
Therefore the atomic number is 20 . We know that mass of proton is 1837 times that of electron, therefore total positive charge present is `20x1837 =36740`,
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