(a) `H_(2)+Br_(2)to2HBr`
(b) `HBr+NaOHtoNaBr+H_(2)O`
(c ) `2NaBr+Cl_(2) to2NaCl+Br_(2)`
(d) `2NaCl to2Na+Cl_(2)` Arrange the above reactions in order s double displacement reaction, combination reaction, decomposition reaction and displacement reaction.

Options

A. badc
B. bdac
C. bacd
D. abdc

Explanation

To arrange the given reactions in the order of double displacement reaction, combination reaction, decomposition reaction, and displacement reaction, we can analyze each reaction step by step:

### Step 1: Identify the Types of Reactions

1. **Reaction (a): `H2 + Br2 → 2HBr`**
- This reaction involves two reactants (H2 and Br2) combining to form a single product (HBr).
- **Type:** Combination Reaction

2. **Reaction (b): `HBr + NaOH → NaBr + H2O`**
- In this reaction, the ions (H+ from HBr and OH- from NaOH) exchange partners to form new products (NaBr and H2O).
- **Type:** Double Displacement Reaction

3. **Reaction (c): `2NaBr + Cl2 → 2NaCl + Br2`**
- Here, Cl2 displaces Br from NaBr to form NaCl and Br2. This is a classic example of a displacement reaction.
- **Type:** Displacement Reaction

4. **Reaction (d): `2NaCl → 2Na + Cl2`**
- In this reaction, NaCl decomposes into its constituent elements, sodium (Na) and chlorine (Cl2).
- **Type:** Decomposition Reaction

### Step 2: Arrange the Reactions

Based on the identified types of reactions, we can arrange them as follows:

1. **Double Displacement Reaction:** (b) `HBr + NaOH → NaBr + H2O`
2. **Combination Reaction:** (a) `H2 + Br2 → 2HBr`
3. **Decomposition Reaction:** (d) `2NaCl → 2Na + Cl2`
4. **Displacement Reaction:** (c) `2NaBr + Cl2 → 2NaCl + Br2`

### Final Order:

- **B (Double Displacement)**
- **A (Combination)**
- **D (Decomposition)**
- **C (Displacement)**

### Summary of the Order:
The order of the reactions is:
1. Double Displacement: (b)
2. Combination: (a)
3. Decomposition: (d)
4. Displacement: (c)