Compare bond order in `N_(2) and N_(2)^(+)`.

Explanation

To compare the bond order in \(N_2\) and \(N_2^+\), we will follow these steps:

### Step 1: Determine the electron configuration of \(N_2\)

1. The nitrogen atom has an atomic number of 7, which means each nitrogen atom has 7 electrons. Therefore, \(N_2\) has a total of \(7 + 7 = 14\) electrons.
2. The electron configuration for \(N_2\) using Molecular Orbital Theory (MOT) is:
- \(\sigma_{1s}^2\)
- \(\sigma^*_{1s}^2\)
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