Arrange `H_(2)O, NH_(3) and CH_(4)` in the decreasing order of bond angle.

Explanation

To arrange \( H_2O \), \( NH_3 \), and \( CH_4 \) in decreasing order of bond angle, we can follow these steps:

### Step 1: Identify the Hybridization
- **Water (\( H_2O \))**: The central atom is oxygen, which has two lone pairs and forms two bonds with hydrogen. The hybridization is \( sp^3 \).
- **Ammonia (\( NH_3 \))**: The central atom is nitrogen, which has one lone pair and forms three bonds with hydrogen. The hybridization is also \( sp^3 \).
- **Methane (\( CH_4 \))**: The central atom is carbon, which has no lone pairs and forms four bonds with hydrogen. The hybridization is \( sp^3 \).

### Step 2: Determine the Bond Angles
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