Molecular formulae and shapes of some molecules are given below. Choose the incorrect match.
`{:("Formula",-,"Shape"),((a)NH_(3),-,"Trigonal pyramidal"),((b)SF_(4),-,"Tetrahedral"),((c )ClF_(3),-,"T-shaped"),((d)PCl_(5),-,"Trigonal bipyramidal"),((e)BF_(3),-,"Trigonal planar"):}`

Explanation

To determine the incorrect match between molecular formulae and their corresponding shapes, we will analyze each option step by step using the hybridization method.

### Step 1: Analyze NH₃ (Ammonia)
- **Valence Electrons (V)**: Nitrogen has 5 valence electrons.
- **Monovalent Atoms (M)**: There are 3 hydrogen atoms attached.
- **Cation Charge (C)**: 0 (no charge).
- **Anion Charge (A)**: 0 (no charge).

Using the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (V + M - C + A) = \frac{1}{2} (5 + 3 - 0 - 0) = \frac{1}{2} (8) = 4 \]
- **Hybridization**: sp³
- **Shape**: Due to one lone pair, the shape is trigonal pyramidal.
- **Match**: Correct (NH₃ is trigonal pyramidal).

### Step 2: Analyze SF₄ (Sulfur Tetrafluoride)
- **Valence Electrons (V)**: Sulfur has 6 valence electrons.
- **Monovalent Atoms (M)**: There are 4 fluorine atoms attached.
- **Cation Charge (C)**: 0.
- **Anion Charge (A)**: 0.

Using the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (6 + 4 - 0 - 0) = \frac{1}{2} (10) = 5 \]
- **Hybridization**: sp³d
- **Shape**: With one lone pair, the shape is seesaw.
- **Match**: Incorrect (Given shape is tetrahedral, but it is actually seesaw).

### Step 3: Analyze ClF₃ (Chlorine Trifluoride)
- **Valence Electrons (V)**: Chlorine has 7 valence electrons.
- **Monovalent Atoms (M)**: There are 3 fluorine atoms attached.
- **Cation Charge (C)**: 0.
- **Anion Charge (A)**: 0.

Using the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (7 + 3 - 0 - 0) = \frac{1}{2} (10) = 5 \]
- **Hybridization**: sp³d
- **Shape**: With two lone pairs, the shape is T-shaped.
- **Match**: Correct (ClF₃ is T-shaped).

### Step 4: Analyze PCl₅ (Phosphorus Pentachloride)
- **Valence Electrons (V)**: Phosphorus has 5 valence electrons.
- **Monovalent Atoms (M)**: There are 5 chlorine atoms attached.
- **Cation Charge (C)**: 0.
- **Anion Charge (A)**: 0.

Using the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (5 + 5 - 0 - 0) = \frac{1}{2} (10) = 5 \]
- **Hybridization**: sp³d
- **Shape**: No lone pairs, so the shape is trigonal bipyramidal.
- **Match**: Correct (PCl₅ is trigonal bipyramidal).

### Step 5: Analyze BF₃ (Boron Trifluoride)
- **Valence Electrons (V)**: Boron has 3 valence electrons.
- **Monovalent Atoms (M)**: There are 3 fluorine atoms attached.
- **Cation Charge (C)**: 0.
- **Anion Charge (A)**: 0.

Using the hybridization formula:
\[ \text{Hybridization} = \frac{1}{2} (3 + 3 - 0 - 0) = \frac{1}{2} (6) = 3 \]
- **Hybridization**: sp²
- **Shape**: No lone pairs, so the shape is trigonal planar.
- **Match**: Correct (BF₃ is trigonal planar).

### Conclusion
The incorrect match is:
- **(b) SF₄** - Given shape is tetrahedral, but it is actually seesaw.