Home
Class 11
CHEMISTRY
At 1127 K and 1 atm pressure, a gaseous ...

At `1127 K` and `1 atm` pressure, a gaseous mixture of `CO` and `CO_(2)` in equilibrium with solid carbon has `90.55% CO` by mass:
`C_((s))+CO_(2(g))hArr2CO_((g))`
Calculate `K_(c)` for the reaction at the above temperature.

Text Solution

Verified by Experts

Mass of drop of water = 0.448 x 1 = 0.448 g
No.of molecules of water =`(0.448xx6.022xx10^23)/18`
`=1.5xx10^22`
No. of hydrogen atoms =`1.5xx10^22xx2`
`=3.0xx10^22`
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Objective D.(MCQs) Passage|10 Videos

  • ENVIRONMENTAL POLLUTION

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|15 Videos

  • HALOALKANES AND HALOARENES

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos

Similar Questions

Explore conceptually related problems

At 1127 K and 1 atm pressure, a gaseous mixture of CO and CO_(2) in equilibrium with solid carbon has 90.55% CO by mass: C_((s))+CO_(2(s))hArr2CO_((g)) Calculate K_(c) for the reaction at the above temperature.

What concentration of CO_(2) be in equilibrium with 0.025 M CO at 120^(@)C for the reaction FeO(s)+CO(g) hArr Fe(s)+CO_(2)(g) if the value of K_(c)=5.0 ?

Calculate the pressure for CO_(2) at equilibrium if DeltaG^(@)=31.1kcal at 300 K for CaCO_(3(s))hArrCaO_((s))+CO_(2(g))

A mixture of one mole of CO_(2) and "mole" of H_(2) attains equilibrium at a temperature of 250^(@)C and a total pressure of 0.1 atm for the change CO_(2)(g)+H_(2)(g) hArr CO(g)+H_(2)O(g) . Calculate K_(p) if the analysis of final reaction mixture shows 0.16 volume percent of CO.

For the reaction C(s)+CO_(2)(g) rarr 2CO(g) an equilibrium mixture has parital pressure, for CO_(2) and CO, of 4.0 and 8.0 atm respectively . K_(p) for the reaction is