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The equilibrium constant of the reaction...

The equilibrium constant of the reaction,
`H_(2)(g)+I_(2)(g)hArr 2HI(g)`
is 64. If the volume of the container is reduced to half of its original volume, the value of equilibrium constant will be :

A

64

B

`(1)/(64)`

C

32

D

16

Text Solution

Verified by Experts

The correct Answer is:
A
Change in volume of container will change the concentrations of the reaction mixture but the equilibrium constant remains unchanged.
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