Two moles of ammonia gas are introduced into a previously evacuated 1 L flask in which it partially dissociates at high temperature as :
`2NH_(3)(g)hArr N_(2)(g)+3H_(2)(g)`
At equilibrium 1.0 mole of `NH_(3)(g)` is found. What is `K_(c )` ?

Options

A. `0.75`
B. `1.5`
C. `1.68
D. `0.46`

Answer

C

Explanation

`{:(,2NH_(3)(g),hArr,N_(2)(g),+,3H_(2)(g)),("Initial conc.",2,,0,,0),("At. equal.",1,,0.5,,1.5):}`
`K=([N_(2)][H_(2)]^(3))/([NH_(3)]^(2))`
`=((0.5)(1.5)^(3))/((1)^(2))=1.7`