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For the reaction : N(2)O(4)(g)hArr ...

For the reaction :
`N_(2)O_(4)(g)hArr 2NO_(2)(g)`
the concentration of the equilibrium mixture at 300 K are `[N_(2)O_(4)]=4.8xx10^(-2)mol L^(-1)` and `[NO_(2)]=1.2xx10^(-2)mol L^(-1). K_(c )` for the reaction is :

A

`0.25`

B

`3xx10^(-1)mol L^(-1)`

C

`3xx10^(3)mol L^(-1)`

D

`3xx10^(-3)mol L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(c )=([NO_(2)]^(2))/([N_(2)O_(4)])`
`=((1.2xx10^(-2))^(2))/((4.8xx10^(-2)))`
`=3xx10^(-3)mol L^(-1)`
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