1.1 mole of A are mixed with 2.2 mole of B and the mixture is then kept in a 1 L vessel till the equilibrium :
`A+2B hArr 2C+D`
is reached. At equilibrium 0.2 moles of C are formed. The equilibrium constant for the reaction is :

Options

A. `0.001`
B. `0.002`
C. `0.003`
D. `0.004`

Answer

A

Explanation

`K=([C]^(2)[D])/([A][B]^(2))`
`[C]=0.2[D]=0.1, [A] =1.1-0.1=1.0`,
`[B]=2.2-0.2=2.0`
`therefore K=((0.2)^(2)(0.1))/((1.0)(2.0)^(2))=0.001`