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For the reaction : 2NO(2)(g)hArr 2NO...

For the reaction :
`2NO_(2)(g)hArr 2NO(g)+O_(2)(g)`
`K_(c )=1.8xx10^(-6)` at `185^(@)C`, the value of `K_(c )` for the reaction
`NO+(1)/(2)O_(2)=NO_(2)` is :

A

`0.9xx10^(6)`

B

`7.5xx10^(2)`

C

`1.95xx10^(-3)`

D

`1.95xx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`2NO_(2)(g)hArr 2NO(g)+O_(2)(g)K_(c )=1.8xx10^(-6)`
`2NO+O_(2)hArr 2NO_(2)K.=(1)/(1.8xx10^(-6))`
`NO+(1)/(2)O_(2)hArr NO_(2)`
`K..=sqrt((1)/(1.8xx10^(-6)))=7.45xx10^(2)`
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