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At 90^(@)C, pure water has [H(3)O^(+)]=1...

At `90^(@)C`, pure water has `[H_(3)O^(+)]=10^(-6)mol L^(-)`. The value of `K_(w)` at `90^(@)C` is :

A

`1xx10^(-6)`

B

`1xx10^(-8)`

C

`1xx10^(-12)`

D

`1xx10^(-14)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(w)=[H_(3)O]^(+)[OH^(-)]=[H_(3)O^(+)]^(2)`
`=(10^(-6))^(2)=10^(-12)`.
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