The concentration of `Ag^(+)` ion in a given saturated solution of AgCl at `25^(@)C` is `1.06xx10^(-5)g` ion per litre. Thus, the solubility product of AgCl is :

Options

A. `0.353xx10^(-10)`
B. `0.530xx10^(-10)`
C. `1.12xx10^(-10)`
D. `2.12xx10^(-10)`

Answer

C

Explanation

`K_(sp)=[Ag^(+)][Cl^(-)]`
`[Ag^(+)]=1.06xx10^(-5)`
and `[Cl^(-)]=1.06xx10^(-5)`
`K_(sp)=(1.06xx10^(-5))xx(1.06xx10^(-5))`
`=1.12xx10^(-10)`