The equilibrium constant for the reaction
`2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g)`
is 256 at 1000 K. The equilibrium constant for the reaction :
`SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g)` is :

Options

A. 16
B. `(1)/(256)`
C. 256
D. `(1)/(16)`

Answer

D

Explanation

For the reaction :
`SO_(3)(g)hArr SO_(2)(g)+(1)/(2)O_(2)(g), K.`
`2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g), K=256`
`therefore K.=sqrt((1)/(256))=(1)/(16)`