At a given temperature, the equilibrium constant for the reaction :
`PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`
is `2.4xx10^(-3)`. At the same temperature, the equilibrium constant for the reaction :
`PCl_(3)(g)+Cl_(2)(g) harr PCl_(5)(g)` is :

Options

A. `2.4xx10^(-3)`
B. `-2.4xx10^(-3)`
C. `4.2xx10^(2)`
D. `4.8xx10^(-2)`

Answer

C

Explanation

Equilibrium constant `=(1)/(2.4xx10^(-3))`
`=4.2xx10^(2)`