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The solubility of a compound MX(2) at 25...

The solubility of a compound `MX_(2)` at `25^(@)C` is `5.0xx10^(-3)` mol/L. Its solubility product at that temperature is :

A

`25xx10^(-6)`

B

`5.0xx10^(-11)`

C

`5.0xx10^(-7)`

D

`1.25xx10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
C
`MX_(2)hArr M^(2+)+2X^(-)`
`K_(sp)=(x)(2x)^(2)=4x^(3)`
`=4xx(5.0xx10^(-3))^(3)`
`=5.0xx10^(-7)`
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