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Ammonium cyanide is a salt of NH(4)OH(K(...

Ammonium cyanide is a salt of `NH_(4)OH(K_(b)=1.8xx10^(-5))` and HCN `(K_(a)=4.0xx10^(-10))`. The hydrolysis constant of 0.1 M `NH_(4)CN` at `25^(@)C` is :

A

`1.4`

B

`7.2xx10^(-15)`

C

`7.2xx10^(-1)`

D

`1.4xx10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(h)=(K_(w))/(K_(a)xx K_(b))`
`=(1xx10^(-14))/(4.0xx10^(-10)xx1.8xx10^(-5))=1.4`
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