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At 298 K, the solubility product of MI i...

At 298 K, the solubility product of MI is `10^(-6)` (conc. Are expressed as mol `kg^(-1)`). The solubility of MI in 0.1 molal KI solution is :

A

`10^(-6)mol kg^(-1)`

B

`10^(-5)mol kg^(-1)`

C

`10^(-4)mol kg^(-1)`

D

`10^(-3)mol kg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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