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The following equilibrium constants are ...

The following equilibrium constants are given :
`N_(2)+3H_(2)hArr 2NH_(3), K_(1)`
`N_(2)+O_(2)hArr 2NO, K_(2)`
`H_(2)+(1)/(2)O_(2)hArr H_(2)O, K_(3)`
The equilibrium constant for the oxidation of `NH_(3)` by oxygen to give NO is :

A

`K_(2)K_(3)^(2)/K_(1)`

B

`K_(2)^(2)K_(3)//K_(1)`

C

`K_(1)K_(2)//K_(3)`

D

`K_(2)K_(3)^(3)//K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`2NH_(3)rarr N_(2)+3H_(2)(1)/(K_(1))`
`3H_(2)+(3)/(2)O_(2)rarr 3H_(2)O " " K_(3)^(3)`
`N_(2)+O_(2)rarr 2NO " " K_(2)`
`2NH_(3)+(5)/(2)O_(2)rarr 2NO+3H_(2)O`
`therefore K=(K_(2)K_(3)^(3))/(K_(1))`
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