When equal volume of the following solutions are mixed, precipitation of `AgCl (K_(sp)=1.8xx10^(-10))` will occur only with :

Options

A. `10^(-3)M Ag^(+)` and `10^(-5)M Cl^(-)`
B. `10^(-5)M Ag^(+)` and `10^(-5)M Cl^(-)`
C. `10^(-6)M Ag^(+)` and `10^(-5)M Cl^(-)`
D. `10^(-4)M Ag^(+)` and `10^(-4)M Cl^(-)`

Answer

D

Explanation

Ionic product `=[Ag^(+)][Cl^(-)]`
`=(10^(-4))/(2)xx(10^(-4))/(2)=2.5xx10^(-9)`
Since ionic product is greater than solubility product precipition will take place.