If the concentration of `OH^(-)` ions in the reaction
`Fe(OH)_(3)(s)hArr Fe^(3+)(aq)+3OH^(-)(aq)`
is decreased by 1/4 times, then equilibrium concentration of `Fe^(3+)` will increase by

Options

A. 8 times
B. 16 times
C. 64 times
D. 4 times

Answer

C

Explanation

`Fe(OH)_(3)(s)hArr Fe^(3+)(aq)+3OH^(-)(aq)`
`K=[Fe^(3+)][OH^(-)]^(3)`
Concentration of `OH^(-)` ion in the reaction is decreased by 1/4 times, then equilibrium concentration of `Fe^(3+)` will be increased by `(4)^(3)=-64` times in order to keep the value of K to be constant.