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A solution of 10^(-3)M each in Mn^(2+), ...

A solution of `10^(-3)M` each in `Mn^(2+), Fe^(2+), Zn^(2+)` and `Hg^(2+)` is heated with `10^(-16)` M sulphide ion. If `K_(sp)` of MnS, FeS, ZnS and HgS are `10^(-15), 10^(-23), 10^(-20)` nd `10^(-54)` respectively which one will precipitate first ?

A

FeS

B

MnS

C

HgS

D

ZnS

Text Solution

Verified by Experts

The correct Answer is:
C
HgS which has larger `K_(sp)` value.
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