Phosphorus pentachloride dissociates as follows in a closed vesselm
`PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`.
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PCl_(5)` is x, the partial pressure of `PCl_(3)` will be :

Options

A. `((2x)/(1-x))P`
B. `((x)/(x-1))P`
C. `((x)/(1-x))P`
D. `((x)/(1+x))P`

Answer

D

Explanation

`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("At equilibrium",1-x,,x,,x):}`
Total moles `=1-x+x+x=1+x`
Partial pressure of `PCl_(3)=((x)/(1+x))P`.