Home
Class 12
CHEMISTRY
0.023g of sodium metal is reacted with 1...

0.023g of sodium metal is reacted with `100 cm^(3)` of water. The pH of the resulting solution is :

A

10

B

11

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
D
`2Na(s)+H_(2)O(l)hArr 2NaOH(aq)+H_(2)`
Weight of `Na=0.023 g`
Moles of `Na=(0.023)/(23)=0.001` mol
2 moles of Na produce 2 moles of NaOH
`therefore 0.001` mol of Na produce 0.002 moles of NaOH
Volume of solution `~~` Volume of water `=100cm^(3)`
`therefore` Molarity of NaOH
`=("No of moles of NaOH" xx 1000)/("Volume of water"(cm^(3)))`
`=(0.002)/(100)xx 1000=0.02 M`
`therefore pOH =-log [OH^(-)]=-log (0.02)`
`=-log (2xx10^(-2))`
`=-log 2-log log 10^(-2)`
`=-0.3010+2`
`=1.6990`
`pH+pOH=14`
`pH+1.6990=14`
`pH=14-1.6990`
`=12.301`.
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level - III)|13 Videos

  • ENVIROMENTAL POLLUTION

    MODERN PUBLICATION|Exercise RECENT EXAMINATION QUESTIOS|2 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    MODERN PUBLICATION|Exercise Recent Examination Questions|13 Videos

Similar Questions

Explore conceptually related problems

Four grams of sodium hydroxide have been added to 10^(3)L tank of water. The pH of resulting solution is :

100 ml of 0.1 N NaOH are mixed with 100 ml of 0.2 N HCl solution and the whole solution is made upto 1 litre. The pH of the resulting solution is :

1 ml of 0.1 N HCl is added to 1 L solution of sodium chloride. The pH of the resulting solution is

A buffer solution contains 0.1 mole of sodium acetate dissolved in 1000 cm^(3) of 0.1 M acetic acid. To the above buffer solution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resulting buffer is