Home
Class 12
CHEMISTRY
Oxidation number of solution in sodium a...

Oxidation number of solution in sodium amalgam (Na/Hg) is

A

0

B

`+1`

C

`-1`

D

`+2`

Text Solution

Verified by Experts

The correct Answer is:
A
Sodium exists in elemental form
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level - II )|35 Videos

  • REDOX REACTIONS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level - III )|2 Videos

  • PURIFICATION AND CHARACTERISATION OF ORGANIC COMPOUNDS

    MODERN PUBLICATION|Exercise Recent Examination Question|4 Videos

  • SOLUTIONS

    MODERN PUBLICATION|Exercise Recent Examination Questions|13 Videos

Similar Questions

Explore conceptually related problems

The oxidation number of boron in Na_(2)B_(4)O_(7) is :

Oxidation state of oxygen atom in sodium peroxide is :

Explain why an aqueous solution of sodium sulphate is neutral while an aqueous of sodium carbonate is basic in nature.

When an aqueous solution containing sodium acetate and sodium propionate is electrolyzed we get

Electrolysis of a concentrated solution of sodium fumarate gives :

25.3 of sodium carbonate , Na_2CO_3 is dissolved in enough water to make 250 ml of solution. If sodium carbonate dissociates completely molar concentration of sodium ion, Na^+ and carbonate ions, CO_3^(2-) are respectively (Molar mass of Na_2CO_3=106 g mol^(-1) ).